Trigonometry/Law of Sines

From Wikibooks, the open-content textbooks collection

< Trigonometry
Jump to: navigation, search

Consider this triangle:

It has three sides

  • A, length A, opposite angle a at vertex a
  • B, length B, opposite angle b at vertex b
  • C, length C, opposite angle c at vertex c

The perpendicular, oc, from line ab to vertex c has length h

The Law of Sines states that:

{A \over \sin a} = {B \over \sin b} = {C \over \sin c}

The law can also be written as the reciprocal:

{\sin a \over A} = {\sin b \over B} = {\sin c \over C}

[edit] Proof

The perpendicular, oc, splits this triangle into two right-angled triangles. This lets us calculate h in two different ways

  • Using the triangle cao gives
h=B \sin a \,
  • Using the triangle cbo gives
h=A \sin b \,
  • Eliminate h from these two equations
A \sin b =B \sin a \,
  • Rearrange
{A \over \sin a} = {B \over \sin b}

By using the other two perpendiculars the full law of sines can be proved. QED.

Personal tools
Create a book
  • Add wiki page
  • Collections help