- 1 A list is a sequence
- 2 Lists are mutable
- 3 Traversing a list
- 4 List operations
- 5 List slices
- 6 List methods
- 7 Map, filter and reduce
- 8 Deleting elements
- 9 Lists and strings
- 10 Objects and values
- 11 Aliasing
- 12 List arguments
- 13 Debugging
- 14 Glossary
- 15 Exercises
A list is a sequence
Like a string, a list is a sequence of values. In a string, the values are characters; in a list, they can be any type. The values in list are called elements or sometimes items.
There are several ways to create a new list; the simplest is to enclose the elements in square brackets (
[10, 20, 30, 40] ['crunchy frog', 'ram bladder', 'lark vomit']
The first example is a list of four integers. The second is a list of three strings. The elements of a list don’t have to be the same type. The following list contains a string, a float, an integer, and (lo!) another list:
['spam', 2.0, 5, [10, 20]]
A list within another list is nested.
A list that contains no elements is called an empty list; you can create one with empty brackets,
As you might expect, you can assign list values to variables:
>>> cheeses = ['Cheddar', 'Edam', 'Gouda'] >>> numbers = [17, 123] >>> empty =  >>> print cheeses, numbers, empty ['Cheddar', 'Edam', 'Gouda'] [17, 123] 
Lists are mutable
The syntax for accessing the elements of a list is the same as for accessing the characters of a string—the bracket operator. The expression inside the brackets specifies the index. Remember that the indices start at 0:
>>> print cheeses Cheddar
Unlike strings, lists are mutable. When the bracket operator appears on the left side of an assignment, it identifies the element of the list that will be assigned.
>>> numbers = [17, 123] >>> numbers = 5 >>> print numbers [17, 5]
The one-eth element of numbers, which used to be 123, is now 5.
You can think of a list as a relationship between indices and elements. This relationship is called a mapping; each index “maps to” one of the elements. Here is a state diagram showing cheeses, numbers and empty:
Lists are represented by boxes with the word “list” outside and the elements of the list inside. cheeses refers to a list with three elements indexed 0, 1 and 2. numbers contains two elements; the diagram shows that the value of the second element has been reassigned from 123 to 5. empty refers to a list with no elements.
List indices work the same way as string indices:
- Any integer expression can be used as an index.
- If you try to read or write an element that does not exist, you get an IndexError.
- If an index has a negative value, it counts backward from the end of the list.
The in operator also works on lists.
>>> cheeses = ['Cheddar', 'Edam', 'Gouda'] >>> 'Edam' in cheeses True >>> 'Brie' in cheeses False
Traversing a list
The most common way to traverse the elements of a list is with a for loop. The syntax is the same as for strings:
for cheese in cheeses: print cheese
This works well if you only need to read the elements of the list. But if you want to write or update the elements, you need the indices. A common way to do that is to combine the functions range and len:
for i in range(len(numbers)): numbers[i] = numbers[i] * 2
This loop traverses the list and updates each element. len returns the number of elements in the list. range returns a list of indices from 0 to n−1, where n is the length of the list. Each time through the loop i gets the index of the next element. The assignment statement in the body uses i to read the old value of the element and to assign the new value.
A for loop over an empty list never executes the body:
for x in empty: print 'This never happens.'
Although a list can contain another list, the nested list still counts as a single element. The length of this list is four:
['spam', 1, ['Brie', 'Roquefort', 'Pol le Veq'], [1, 2, 3]]
The + operator concatenates lists:
>>> a = [1, 2, 3] >>> b = [4, 5, 6] >>> c = a + b >>> print c [1, 2, 3, 4, 5, 6]
Similarly, the * operator repeats a list a given number of times:
>>>  * 4 [0, 0, 0, 0] >>> [1, 2, 3] * 3 [1, 2, 3, 1, 2, 3, 1, 2, 3]
The first example repeats  four times. The second example repeats the list [1, 2, 3] three times.
The slice operator also works on lists:
>>> t = ['a', 'b', 'c', 'd', 'e', 'f'] >>> t[1:3] ['b', 'c'] >>> t[:4] ['a', 'b', 'c', 'd'] >>> t[3:] ['d', 'e', 'f']
If you omit the first index, the slice starts at the beginning. If you omit the second, the slice goes to the end. So if you omit both, the slice is a copy of the whole list.
>>> t[:] ['a', 'b', 'c', 'd', 'e', 'f']
Since lists are mutable, it is often useful to make a copy before performing operations that fold, spindle or mutilate lists.
A slice operator on the left side of an assignment can update multiple elements:
>>> t = ['a', 'b', 'c', 'd', 'e', 'f'] >>> t[1:3] = ['x', 'y'] >>> print t ['a', 'x', 'y', 'd', 'e', 'f']
Python provides methods that operate on lists. For example, append adds a new element to the end of a list:
>>> t = ['a', 'b', 'c'] >>> t.append('d') >>> print t ['a', 'b', 'c', 'd']
extend takes a list as an argument and appends all of the elements:
>>> t1 = ['a', 'b', 'c'] >>> t2 = ['d', 'e'] >>> t1.extend(t2) >>> print t1 ['a', 'b', 'c', 'd', 'e']
This example leaves t2 unmodified.
sort arranges the elements of the list from low to high:
>>> t = ['d', 'c', 'e', 'b', 'a'] >>> t.sort() >>> print t ['a', 'b', 'c', 'd', 'e']
List methods are all void; they modify the list and return None. If you accidentally write t = t.sort(), you will be disappointed with the result.
Map, filter and reduce
To add up all the numbers in a list, you can use a loop like this:
def add_all(t): total = 0 for x in t: total += x return total
total is initialized to 0. Each time through the loop, x gets one element from the list. The += operator provides a short way to update a variable:
total += x
is equivalent to:
total = total + x
As the loop executes, total accumulates the sum of the elements; a variable used this way is sometimes called an accumulator.
Adding up the elements of a list is such a common operation that Python provides it as a built-in function, sum:
>>> t = [1, 2, 3] >>> sum(t) 6
An operation like this that combines a sequence of elements into a single value is sometimes called reduce.
Sometimes you want to traverse one list while building another. For example, the following function takes a list of strings and returns a new list that contains capitalized strings:
def capitalize_all(t): res =  for s in t: res.append(s.capitalize()) return res
res is initialized with an empty list; each time through the loop, we append the next element. So res is another kind of accumulator.
An operation like
capitalize_all is sometimes called a map because it “maps” a function (in this case the method capitalize) onto each of the elements in a sequence.
Another common operation is to select some of the elements from a list and return a sublist. For example, the following function takes a list of strings and returns a list that contains only the uppercase strings:
def only_upper(t): res =  for s in t: if s.isupper(): res.append(s) return res
isupper is a string method that returns True if the string contains only upper case letters.
An operation like
only_upper is called a filter because it selects some of the elements and filters out the others.
Most common list operations can be expressed as a combination of map, filter and reduce. Because these operations are so common, Python provides language features to support them, including the built-in function map and an operator called a “list comprehension.”
Write a function that takes a list of numbers and returns the cumulative sum; that is, a new list where the 'i'th element is the sum of the first 'i+1' elements from the original list. For example, the cumulative sum of '[1, 2, 3]' is '[1, 3, 6]'.
There are several ways to delete elements from a list. If you know the index of the element you want, you can use pop:
>>> t = ['a', 'b', 'c'] >>> x = t.pop(1) >>> print t ['a', 'c'] >>> print x b
pop modifies the list and returns the element that was removed. If you don’t provide an index, it deletes and returns the last element.
If you don’t need the removed value, you can use the del operator:
>>> t = ['a', 'b', 'c'] >>> del t >>> print t ['a', 'c']
If you know the element you want to remove (but not the index), you can use remove:
>>> t = ['a', 'b', 'c'] >>> t.remove('b') >>> print t ['a', 'c']
The return value from remove is None.
To remove more than one element, you can use del with a slice index:
>>> t = ['a', 'b', 'c', 'd', 'e', 'f'] >>> del t[1:5] >>> print t ['a', 'f']
As usual, the slice selects all the elements up to, but not including, the second index.
Lists and strings
A string is a sequence of characters and a list is a sequence of values, but a list of characters is not the same as a string. To convert from a string to a list of characters, you can use list:
>>> s = 'spam' >>> t = list(s) >>> print t ['s', 'p', 'a', 'm']
Because list is the name of a built-in function, you should avoid using it as a variable name. I also avoid l because it looks too much like 1. So that’s why I use t.
The list function breaks a string into individual letters. If you want to break a string into words, you can use the split method:
>>> s = 'pining for the fjords' >>> t = s.split() >>> print t ['pining', 'for', 'the', 'fjords']
An optional argument called a delimiter specifies which characters to use as word boundaries. The following example uses a hyphen as a delimiter:
>>> s = 'spam-spam-spam' >>> delimiter = '-' >>> s.split(delimiter) ['spam', 'spam', 'spam']
join is the inverse of split. It takes a list of strings and concatenates the elements. join is a string method, so you have to invoke it on the delimiter and pass the list as a parameter:
>>> t = ['pining', 'for', 'the', 'fjords'] >>> delimiter = ' ' >>> delimiter.join(t) 'pining for the fjords'
In this case the delimiter is a space character, so join puts a space between words. To concatenate strings without spaces, you can use the empty string, , as a delimiter.
Objects and values
If we execute these assignment statements:
a = 'banana' b = 'banana'
We know that a and b both refer to a string, but we don’t know whether they refer to the same string. There are two possible states:
In one case, a and b refer to two different objects that have the same value. In the second case, they refer to the same object.
To check whether two variables refer to the same object, you can use the is operator.
>>> a = 'banana' >>> b = 'banana' >>> a is b True
In this example, Python only created one string object, and both a and b refer to it.
But when you create two lists, you get two objects:
>>> a = [1, 2, 3] >>> b = [1, 2, 3] >>> a is b False
So the state diagram looks like this:
In this case we would say that the two lists are equivalent, because they have the same elements, but not identical, because they are not the same object. If two objects are identical, they are also equivalent, but if they are equivalent, they are not necessarily identical.
Until now, we have been using “object” and “value” interchangeably, but it is more precise to say that an object has a value. If you execute a = [1,2,3], a refers to a list object whose value is a particular sequence of elements. If another list has the same elements, we would say it has the same value.
If a refers to an object and you assign b = a, then both variables refer to the same object:
>>> a = [1, 2, 3] >>> b = a >>> b is a True
The state diagram looks like this:
The association of a variable with an object is called a reference. In this example, there are two references to the same object.
An object with more than one reference has more than one name, so we say that the object is aliased.
If the aliased object is mutable, changes made with one alias affect the other:
>>> b = 17 >>> print a [17, 2, 3]
Although this behavior can be useful, it is error-prone. In general, it is safer to avoid aliasing when you are working with mutable objects.
For immutable objects like strings, aliasing is not as much of a problem. In this example:
a = 'banana' b = 'banana'
It almost never makes a difference whether a and b refer to the same string or not.
When you pass a list to a function, the function gets a reference to the list. If the function modifies a list parameter, the caller sees the change. For example,
delete_head removes the first element from a list:
def delete_head(t): del t
Here’s how it is used:
>>> letters = ['a', 'b', 'c'] >>> delete_head(letters) >>> print letters ['b', 'c']
The parameter t and the variable letters are aliases for the same object. The stack diagram looks like this:
Since the list is shared by two frames, I drew it between them.
It is important to distinguish between operations that modify lists and operations that create new lists. For example, the append method modifies a list, but the + operator creates a new list:
>>> t1 = [1, 2] >>> t2 = t1.append(3) >>> print t1 [1, 2, 3] >>> print t2 None >>> t3 = t1 +  >>> print t3 [1, 2, 3] >>> t2 is t3 False
This difference is important when you write functions that are supposed to modify lists. For example, this function does not delete the head of a list:
def bad_delete_head(t): t = t[1:] # WRONG!
The slice operator creates a new list and the assignment makes t refer to it, but none of that has any effect on the list that was passed as an argument.
An alternative is to write a function that creates and returns a new list. For example, tail returns all but the first element of a list:
def tail(t): return t[1:]
This function leaves the original list unmodified. Here’s how it is used:
>>> letters = ['a', 'b', 'c'] >>> rest = tail(letters) >>> print rest ['b', 'c']
Write a function called 'chop' that takes a list and modifies it, removing the first and last elements, and returns 'None'.
Then write a function called 'middle' that takes a list and returns a new list that contains all but the first and last elements.
Careless use of lists (and other mutable objects) can lead to long hours of debugging. Here are some common pitfalls and ways to avoid them:
- Don’t forget that most list methods modify the argument and
return None. This is the opposite of the string methods, which return a new string and leave the original alone. If you are used to writing string code like this:
word = word.strip()
It is tempting to write list code like this:
t = t.sort() # WRONG!
Because sort returns None, the next operation you perform with t is likely to fail.
Before using list methods and operators, you should read the documentation carefully and then test them in interactive mode. The methods and operators that lists share with other sequences (like strings) are documented at docs.python.org/lib/typesseq.html. The methods and operators that only apply to mutable sequences are documented at docs.python.org/lib/typesseq-mutable.html.
- Pick an idiom and stick with it.
Part of the problem with lists is that there are too many ways to do things. For example, to remove an element from a list, you can use pop, remove, del, or even a slice assignment.
To add an element, you can use the append method or the + operator. But don’t forget that these are right:
t.append(x) t = t + [x]
And these are wrong:
t.append([x]) # WRONG! t = t.append(x) # WRONG! t + [x] # WRONG! t = t + x # WRONG!
Try out each of these examples in interactive mode to make sure you understand what they do. Notice that only the last one causes a runtime error; the other three are legal, but they do the wrong thing.
- Make copies to avoid aliasing.
If you want to use a method like sort that modifies the argument, but you need to keep the original list as well, you can make a copy.
orig = t[:] t.sort()
In this example you could also use the built-in function sorted, which returns a new, sorted list and leaves the original alone. But in that case you should avoid using sorted as a variable name!
- A sequence of values.
- One of the values in a list (or other sequence), also called items.
- An integer value that indicates an element in a list.
- nested list:
- A list that is an element of another list.
- list traversal:
- The sequential accessing of each element in a list.
- A relationship in which each element of one set corresponds to an element of another set. For example, a list is a mapping from indices to elements.
- A variable used in a loop to add up or accumulate a result.
- A processing pattern that traverses a sequence and accumulates the elements into a single result.
- A processing pattern that traverses a sequence and performs an operation on each element.
- A processing pattern that traverses a list and selects the elements that satisfy some criterion.
- Something a variable can refer to. An object has a type and a value.
- Having the same value.
- Being the same object (which implies equivalence).
- The association between a variable and its value.
- A circumstance where two variables refer to the same object.
- A character or string used to indicate where a string should be split.
Write a function called
is_sorted that takes a list as a parameter and returns 'True' if the list is sorted in ascending order and 'False' otherwise. You can assume (as a precondition) that the elements of the list can be compared with the comparison operators '<', '>', etc.
is_sorted([1,2,2]) should return 'True' and
is_sorted(['b','a']) should return 'False'.
Two words are anagrams if you can rearrange the letters from one to spell the other. Write a function called
is_anagram that takes two strings and returns 'True' if they are anagrams.
The (so-called) Birthday Paradox:
Write a function called
has_duplicates that takes a list and returns 'True' if there is any element that appears more than once. It should not modify the original list.
- If there are 23 students in your class, what are the chances
that two of you have the same birthday? You can estimate this probability by generating random samples of 23 birthdays and checking for matches. Hint: you can generate random birthdays with the 'randint' function in the 'random' module.
You can read about this problem at 'wikipedia.org/wiki/Birthday_paradox', and you can see my solution at 'thinkpython.com/code/birthday.py'.
Write a function called
remove_duplicates that takes a list and returns a new list with only the unique elements from the original. Hint: they don’t have to be in the same order.
Write a function that takess the file 'words.txt' and builds a list with one element per word. Write two versions of this function, one using the 'append' method and the other using the idiom 't = t + [x]'. Which one takes longer to run? Why?
You can see my solution at 'thinkpython.com/code/wordlist.py'.
To check whether a word is in the word list, you could use the 'in' operator, but it would be slow because it searches through the words in order.
Because the words are in alphabetical order, we can speed things up with a bisection search, which is similar to what you do when you look a word up in the dictionary. You start in the middle and check to see whether the word you are looking for comes before the word in the middle of the list. If so, then you search the first half of the list the same way. Otherwise you search the second half.
Either way, you cut the remaining search space in half. If the word list has 113,809 words, it will take about 17 steps to find the word or conclude that it’s not there.
Write a function called 'bisect' that takes a sorted list and a target value and returns the index of the value in the list, if it’s there, or 'None' if it’s not.
Or you could read the documentation of the 'bisect' module and use that!
Two words are a “reverse pair” if each is the reverse of the other. Write a program that finds all the reverse pairs in the word list.
Two words “interlock” if taking alternating letters from each forms a new word1. For example, “shoe” and “cold” interlock to form “schooled.”
- Write a program that finds all pairs of words that interlock.
Hint: don’t enumerate all pairs!
- Can you find any words that are three-way interlocked; that is,
every third letter forms a word, starting from the first, second or third?
- This exercise is inspired by an example at puzzlers.org.