1500 families with two children are selected randomly according to the data given below.

Number of girls in a family | 0 | 1 | 2 |

Number of families | 211 | 814 | 475 |

Compute the probability of a family, chosen at random, having

(i) 2 girls

(ii) 1 girl

(iii) no girl

Also, check whether the sum of these probabilities is 1.

Maths

Class 9

1073

Valentina

Knowledge

Answer / Solution

Answer / Solution

Here, Total number of families = 1500

(i) Number of families having 2 girls = 475, therefore, Probability of selecting a family having 2 girls equals = 475 / 1500 = 19 / 60

(ii) Number of families having 1 girl = 814, therefore, Probability of selecting a family having 1 girl = 814 / 1500 = 407 / 750

(iii) Number of families having no girl = 211, therefore, Probability of selecting a family having no girl = 211 / 1500.

Now, the sum of the obtained probabilities are = 19/60 + 407/750 + 211/1500

= (475 + 814 + 211)1500 = 1500/1500 = 1

i.e., Sum of the above probabilities is equal to 1.

Rajiv Sharma

Answer / Solution

Answer / Solution

Given that the **total number of families is 1500**

- According to the given table,
**families having 2 girls is 475**. Therefore, the probability of having 2 girls in a family = 475 / 1500 = 19 / 60 - According to the given table,
**families having 1 girl is 814**. Therefore, the probability of having 1 girl in a family = 814 / 1500 = 407 / 750 - According to the given table,
**families having no girl = 211**. Therefore, the probability of having no girl in a family = 211 / 1500.

When we add all the three probabilities: **475/60 + 814/750 + 211/1500 = 1500/1500 = 1**.** **Therefore, the sum of the above probabilities is equal to 1 which is equal to 100%.

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