# Ordinary Differential Equations/Homogeneous x and y

Not to be confused with homogeneous equations, an equation homogeneous in x and y of degree n is an equation of the form

F(x,y,y')=0

Such that

.

Then the equation can take the form

Which is essentially another in the form

.

If we can solve this equation for y', then we can easily use the substitution method mentioned earlier to solve this equation. Suppose, however, that it is more easily solved for ,

So that

.

We can differentiate this to get

Then re-arranging things,

So that upon integrating,

We get

Thus, if we can eliminate y' between two simultaneous equations

and

,

then we can obtain the general solution..

## Homogeneous Ordinary Differential Equations[edit | edit source]

A function P is homogeneous of order if . A homogeneous ordinary differential equation is an equation of the form P(x,y)dx+Q(x,y)dy=0 where P and Q are homogeneous of the same order.

The first usage of the following method for solving homogeneous ordinary differential equations was by Leibniz in 1691. Using the substitution y=vx or x=vy, we can make turn the equation into a separable equation.

Now we need to find *v*':

Plug back into the original equation

- Solve for v(x), then plug into the equation of v to get y

Again, don't memorize the equation. Remember the general method, and apply it.

### Example 2[edit | edit source]

Let's use . Solve for *y*'(*x,v,v*')

Now plug into the original equation

Solve for *v*

Plug into the definition of *v* to get *y*.

We leave it in form, since solving for *y* would lose information.

Note that there should be a constant of integration in the general solution. Adding it is left as an exercise.

### Example 3[edit | edit source]

Lets use again. Solve for

Now plug into the original equation

Solve for *v*:

Use the definition of *v* to solve for *y*.

### An equation that is a function of a quotient of linear expressions[edit | edit source]

Given the equation ,

We can make the substitution x=x'+h and y=y'+k where h and k satisfy the system of linear equations:

Which turns it into a homogeneous equation of degree 0: