NonProgrammer's Tutorial for Python 2.6/Boolean Expressions
Here is a little example of boolean expressions (you don't have to type it in):
a = 6
b = 7
c = 42
print 1, a == 6
print 2, a == 7
print 3, a == 6 and b == 7
print 4, a == 7 and b == 7
print 5, not a == 7 and b == 7
print 6, a == 7 or b == 7
print 7, a == 7 or b == 6
print 8, not (a == 7 and b == 6)
print 9, not a == 7 and b == 6
With the output being:
1 True 2 False 3 True 4 False 5 True 6 True 7 False 8 True 9 False
What is going on? The program consists of a bunch of funny looking print
statements. Each print
statement prints a number and an expression. The number is to help keep track of which statement I am dealing with. Notice how each expression ends up being either False
or True
. In Python, false can also be written as 0 and true as 1.
The lines:
print 1, a == 6
print 2, a == 7
print out a True
and a False
respectively just as expected since the first is true and the second is false. The third print, print 3, a == 6 and b == 7
, is a little different. The operator and
means if both the statement before and the statement after are true then the whole expression is true otherwise the whole expression is false. The next line, print 4, a == 7 and b == 7
, shows how if part of an and
expression is false, the whole thing is false. The behavior of and
can be summarized as follows:
expression  result 

true and true

true 
true and false

false 
false and true

false 
false and false

false 
Notice that if the first expression is false Python does not check the second expression since it knows the whole expression is false.
The next line, print 5, not a == 7 and b == 7
, uses the not
operator. not
just gives the opposite of the expression. (The expression could be rewritten as print 5, a != 7 and b == 7
). Here is the table:
expression  result 

not true

false 
not false

true 
The two following lines, print 6, a == 7 or b == 7
and print 7, a == 7 or b == 6
, use the or
operator. The or
operator returns true if the first expression is true, or if the second expression is true or both are true. If neither are true it returns false. Here's the table:
expression  result 

true or true

true 
true or false

true 
false or true

true 
false or false

false 
Notice that if the first expression is true Python doesn't check the second expression since it knows the whole expression is true. This works since or
is true if at least one half of the expression is true. The first part is true so the second part could be either false or true, but the whole expression is still true.
The next two lines, print 8, not (a == 7 and b == 6)
and print 9, not a == 7 and b == 6
, show that parentheses can be used to group expressions and force one part to be evaluated first. Notice that the parentheses changed the expression from false to true. This occurred since the parentheses forced the not
to apply to the whole expression instead of just the a == 7
portion.
Here is an example of using a boolean expression:
list = ["Life", "The Universe", "Everything", "Jack", "Jill", "Life", "Jill"]
# make a copy of the list. See the More on Lists chapter to explain what [:] means.
copy = list[:]
# sort the copy
copy.sort()
prev = copy[0]
del copy[0]
count = 0
# go through the list searching for a match
while count < len(copy) and copy[count] != prev:
prev = copy[count]
count = count + 1
# If a match was not found then count can't be < len
# since the while loop continues while count is < len
# and no match is found
if count < len(copy):
print "First Match:", prev
And here is the output:
First Match: Jill
This program works by continuing to check for match while count < len(copy) and copy[count] is not equal to prev
. When either count
is greater than the last index of copy
or a match has been found the and
is no longer true so the loop exits. The if
simply checks to make sure that the while
exited because a match was found.
The other "trick" of and
is used in this example. If you look at the table for and
notice that the third entry is "false and won't check". If count >= len(copy)
(in other words count < len(copy)
is false) then copy[count]
is never looked at. This is because Python knows that if the first is false then they can't both be true. This is known as a short circuit and is useful if the second half of the and
will cause an error if something is wrong. I used the first expression (count < len(copy)
) to check and see if count
was a valid index for copy
. (If you don't believe me remove the matches "Jill" and "Life", check that it still works and then reverse the order of count < len(copy) and copy[count] != prev
to copy[count] != prev and count < len(copy)
.)
Boolean expressions can be used when you need to check two or more different things at once.
A note on Boolean Operators[edit]
A common mistake for people new to programming is a misunderstanding of the way that boolean operators works, which stems from the way the python interpreter reads these expressions. For example, after initially learning about "and " and "or" statements, one might assume that the expression x == ('a' or 'b')
would check to see if the variable x
was equivalent to one of the strings 'a'
or 'b'
. This is not so. To see what I'm talking about, start an interactive session with the interpreter and enter the following expressions:
>>> 'a' == ('a' or 'b') >>> 'b' == ('a' or 'b') >>> 'a' == ('a' and 'b') >>> 'b' == ('a' and 'b')
And this will be the unintuitive result:
>>> 'a' == ('a' or 'b') True >>> 'b' == ('a' or 'b') False >>> 'a' == ('a' and 'b') False >>> 'b' == ('a' and 'b') True
At this point, the and
and or
operators seem to be broken. It doesn't make sense that, for the first two expressions, 'a'
is equivalent to 'a'
or 'b'
while 'b'
is not. Furthermore, it doesn't make any sense that 'b' is equivalent to 'a'
and 'b'
. After examining what the interpreter does with boolean operators, these results do in fact exactly what you are asking of them, it's just not the same as what you think you are asking.
When the Python interpreter looks at an or
expression, it takes the first statement and checks to see if it is true. If the first statement is true, then Python returns that object's value without checking the second statement. This is because for an or
expression, the whole thing is true if one of the values is true; the program does not need to bother with the second statement. On the other hand, if the first value is evaluated as false Python checks the second half and returns that value. That second half determines the truth value of the whole expression since the first half was false. This "laziness" on the part of the interpreter is called "short circuiting" and is a common way of evaluating boolean expressions in many programming languages.
Similarly, for an and
expression, Python uses a short circuit technique to speed truth value evaluation. If the first statement is false then the whole thing must be false, so it returns that value. Otherwise if the first value is true it checks the second and returns that value.
One thing to note at this point is that the boolean expression returns a value indicating True
or False
, but that Python considers a number of different things to have a truth value assigned to them. To check the truth value of any given object x
, you can use the function bool(x)
to see its truth value. Below is a table with examples of the truth values of various objects:
True  False 

True  False 
1  0 
Numbers other than zero  The string 'None' 
Nonempty strings  Empty strings 
Nonempty lists  Empty lists 
Nonempty dictionaries  Empty dictionaries 
Now it is possible to understand the perplexing results we were getting when we tested those boolean expressions before. Let's take a look at what the interpreter "sees" as it goes through that code:
First case:
>>> 'a' == ('a' or 'b') # Look at parentheses first, so evaluate expression "('a' or 'b')" # 'a' is a nonempty string, so the first value is True # Return that first value: 'a' >>> 'a' == 'a' # the string 'a' is equivalent to the string 'a', so expression is True True
Second case:
>>> 'b' == ('a' or 'b') # Look at parentheses first, so evaluate expression "('a' or 'b')" # 'a' is a nonempty string, so the first value is True # Return that first value: 'a' >>> 'b' == 'a' # the string 'b' is not equivalent to the string 'a', so expression is False False
Third case:
>>> 'a' == ('a' and 'b') # Look at parentheses first, so evaluate expression "('a' and 'b')" # 'a' is a nonempty string, so the first value is True, examine second value # 'b' is a nonempty string, so second value is True # Return that second value as result of whole expression: 'b' >>> 'a' == 'b' # the string 'a' is not equivalent to the string 'b', so expression is False False
Fourth case:
>>> 'b' == ('a' and 'b') # Look at parentheses first, so evaluate expression "('a' and 'b')" # 'a' is a nonempty string, so the first value is True, examine second value # 'b' is a nonempty string, so second value is True # Return that second value as result of whole expression: 'b' >>> 'b' == 'b' # the string 'b' is equivalent to the string 'b', so expression is True True
So Python was really doing its job when it gave those apparently bogus results. As mentioned previously, the important thing is to recognize what value your boolean expression will return when it is evaluated, because it isn't always obvious.
Going back to those initial expressions, this is how you would write them out so they behaved in a way that you want:
>>> 'a' == 'a' or 'a' == 'b' True >>> 'b' == 'a' or 'b' == 'b' True >>> 'a' == 'a' and 'a' == 'b' False >>> 'b' == 'a' and 'b' == 'b' False
When these comparisons are evaluated they return truth values in terms of True or False, not strings, so we get the proper results.
Examples[edit]
password1.py
## This programs asks a user for a name and a password.
# It then checks them to make sure the user is allowed in.
name = raw_input("What is your name? ")
password = raw_input("What is the password? ")
if name == "Josh" and password == "Friday":
print "Welcome Josh"
elif name == "Fred" and password == "Rock":
print "Welcome Fred"
else:
print "I don't know you."
Sample runs
What is your name? Josh What is the password? Friday Welcome Josh
What is your name? Bill What is the password? Money I don't know you.
Exercises[edit]
Write a program that has a user guess your name, but they only get 3 chances to do so until the program quits.
Write a program that has a user guess your name, but they only get 3 chances to do so until the program quits.
print "Try to guess my name!"
count = 3
name = "Tony"
guess = raw_input("What is my name? ")
while count > 1 and guess != name:
print "You are wrong!"
guess = raw_input("What is my name? ")
count = count  1
if guess != name:
print "You are wrong!" # this message isn't printed in the third chance, so we print it now
print "You ran out of chances."
quit
else:
print "Yes! My name is", name + "!"