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Linear Algebra over a Ring/Direct product, direct sum and tensor product

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Definition (free module over a set):

Let S be any set, and let R be a ring. Then the free module F(S) is defined to be the module

Failed to parse (unknown function "\middle"): {\displaystyle F(S) := \left\{ \sum_{k=1}^n r_k s_k \middle| \forall k \in [n]: r_k \in R \wedge s_k \in S \right\}}

together with the module operation

r(∑k=1nrksk)=∑k=1nrrksk

and the obvious addition

∑k=1nrksk+∑k=1nrk′sk′=∑k=1nrksk+∑k=1nrk′sk′.

Definition (tensor product):

Let R be a ring and let M1,…,Mn be R-modules. The tensor product of the modules M1,…,Mn is defined as the R-module

M1⊗M2⊗⋯⊗Mn:=F(M1×M2×⋯×Mn)/K,

where K≤F(M1×M2×⋯×Mn) is the following submodule:

K=⟨{(m1,…,mj−1,mj−rl,mj+1,…,mn)−(m1,…,mn)−r(m1,…,mj−1,l,mj+1,…,mn)|j∈{1,…,n},m1∈M1,…,mn∈Mn,l∈Mj,r∈R}⟩.

Proposition (universal property of the tensor product):

Let R be a ring and let M1,…,Mn be R-modules. Then the tensor product M1⊗⋯⊗Mn satisfies the universal property that for each R-module N and each multilinear map f:M1×⋯×Mn→N, there exists a unique linear map f~:M1⊗⋯⊗Mn→N such that

.

Proposition (tensor product as multifunctor):

Let R be a ring. Then for each n∈ℕ, the tensor product yields a multifunctor

⊕n:(R−𝐌𝐨𝐝)n→R−𝐌𝐨𝐝.

Whenever M1,…,Mn and N1,…,Nn are R-modules and for j∈{1,…,n}, fj:Mj→Nj are morphisms, the morphisms that turn ⊕n into a multifunctor are given by

Failed to parse (unknown function "\begin{align}"): {\displaystyle \begin{align} f_1 \otimes \cdots \otimes f_n: M_1 \otimes \cdots \otimes M_n \to N_1 \otimes \cdots \otimes}

Proposition (associativity of the tensor product):

Let R be a ring