Linear Algebra/Topic: Dimensional Analysis/Solutions
Solutions[edit]
- Problem 1
Consider a projectile, launched with initial velocity , at an angle . An investigation of this motion might start with the guess that these are the relevant quantities. (de Mestre 1990)
quantity | dimensional
formula |
horizontal position | |
vertical position | |
initial speed | Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "/mathoid/local/v1/":): {\displaystyle L^1M^0T^{-1}} |
angle of launch | |
acceleration due to gravity Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "/mathoid/local/v1/":): g | |
time |
- Show that is a complete set of dimensionless products. (Hint. This can be done by finding the appropriate free variables in the linear system that arises, but there is a shortcut that uses the properties of a basis.)
- These two equations of motion for projectiles are familiar: and Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "/mathoid/local/v1/":): {\displaystyle y=v_0\sin(\theta) t- (g/2)t^2} . Manipulate each to rewrite it as a relationship among the dimensionless products of the prior item.
- Answer
- This relationship
- The first equation can be rewritten
- Problem 2
- Einstein (Einstein 1911) conjectured that the infrared characteristic frequencies of a solid may be determined by the same forces between atoms as determine the solid's ordanary elastic behavior. The relevant quantities are
quantity | dimensional
formula |
characteristic frequency | |
compressibility | |
number of atoms per cubic cm | |
mass of an atom |
Show that there is one dimensionless product. Conclude that, in any complete relationship among quantities with these dimensional formulas, is a constant times . This conclusion played an important role in the early study of quantum phenomena.
- Answer
We consider
which gives these relations among the powers.
This is the solution space (because we wish to express as a function of the other quantities, is taken as the parameter).
Thus, is the dimensionless combination, and we have that equals times a constant (the function is constant since it has no arguments).
- Problem 3
The torque produced by an engine has dimensional formula . We may first guess that it depends on the engine's rotation rate (with dimensional formula ), and the volume of air displaced (with dimensional formula ) (Giordano, Wells & Wilde 1987).
- Try to find a complete set of dimensionless products. What goes wrong?
- Adjust the guess by adding the density of the air (with dimensional formula ). Now find a complete set of dimensionless products.
- Answer
- Setting
- Setting
- Problem 4
Dominoes falling make a wave. We may conjecture that the wave speed depends on the the spacing between the dominoes, the height of each domino, and the acceleration due to gravity . (Tilley)
- Find the dimensional formula for each of the four quantities.
- Show that is a complete set of dimensionless products.
- Show that if is fixed then the propagation speed is proportional to the square root of .
- Answer
- These are the dimensional formulas.
quantity dimensional formula
speed of the wave separation of the dominoes height of the dominoes acceleration due to gravity - The relationship
- Buckingham's Theorem says that , and so, since is a constant, if is fixed then is proportional to .
- Problem 5
Prove that the dimensionless products form a vector space under the operation of multiplying two such products and the operation of raising such the product to the power of the scalar. (The vector arrows are a precaution against confusion.) That is, prove that, for any particular homogeneous system, this set of products of powers of , ...,
is a vector space under:
and
(assume that all variables represent real numbers).
- Answer
Checking the conditions in the definition of a vector space is routine.
- Problem 6
The advice about apples and oranges is not right. Consider the familiar equations for a circle and .
- Check that and have different dimensional formulas.
- Produce an equation that is not dimensionally homogeneous (i.e., it adds apples and oranges) but is nonetheless true of any circle.
- The prior item asks for an equation that is complete but not dimensionally homogeneous. Produce an equation that is dimensionally homogeneous but not complete.
(Just because the old saying isn't strictly right, doesn't keep it from being a useful strategy. Dimensional homogeneity is often used as a check on the plausibility of equations used in models. For an argument that any complete equation can easily be made dimensionally homogeneous, see (Bridgman 1931, Chapter I, especially page 15.)
- Answer
- The dimensional formula of the circumference is , that is, . The dimensional formula of the area is .
- One is .
- One example is this formula relating the length of arc subtended by an angle to the radius and the angle measure in radians: . Both terms in that formula have dimensional formula . The relationship holds for some unit systems (inches and radians, for instance) but not for all unit systems (inches and degrees, for instance).
References[edit]
- Bridgman, P. W. (1931), Dimensional Analysis, Yale University Press.
- de Mestre, Neville (1990), The Mathematics of Projectiles in sport, Cambridge University Press.
- Giordano, R.; Wells, M.; Wilde, C. (1987), "Dimensional Analysis", UMAP Modules (COMAP) (526).
- Einstein, A. (1911), Annals of Physics 35: 686.
- Tilley, Burt, Private Communication.