# FHSST Physics/Work and Energy/Energy

# Energy[edit | edit source]

As we mentioned earlier, energy is the capacity to do work. When positive work is done on an object, the system doing the work loses
energy. In fact, **the energy lost by a system is exactly equal to the work done by the system.**

Like work (*W*) the unit of energy (*E*) is the joule (J). This follows as work is just the transfer of energy.

A very important property of our universe which was discovered around 1890 is that energy is conserved.

Energy is never created nor destroyed, but merely

transformed from one form to another.

Energy conservation and the conservation of matter are the principles on which classical mechanics is built.

IN THE ABSENCE OF FRICTIONWhen work is done on an object by a system:

-the object gains energy equal to the work done by the system

Work Done = Energy Transferred

Thermal energy (heat) is the disorganized movement of microscopic particles. Once energy is converted to this form, it has limited usefulness for doing further work in the system. Friction is the general name for forces that converts energy to heat.

IN THE PRESENCE OF FRICTIONWhen work is done by a system: -only some of the energy lost by the system is transferred into useful energy -the rest of the energy transferred is lost to heat by friction Total Work Done = Useful Work Done + Work Done Against Friction

## Types of Energy[edit | edit source]

So what different types of energy exist? Kinetic, mechanical, thermal, chemical, electrical, radiant, and atomic energy are just some of the types that exist. By the principle of conservation of energy, whenwork is done energy is merely transferred from one object to another and from one type of energy to another.

### Kinetic Energy[edit | edit source]

Kinetic energy is the energy of motion that an object has. Objects moving in straight lines possess *translational kinetic energy*,
which we often abbreviate as *E*_{k}.

The translational kinetic energy of an object is given by

E_{k}: kinetic energy ( J)m: mass of object ( kg)v: speed of the object ( m.s^{-1})

Note the dependence of the kinetic energy on the speed of the object- kinetic energy is related to motion. The faster an object is moving the greater its kinetic energy.

#### Worked Example 41 Calculation of Kinetic Energy[edit | edit source]

**Question:** If a rock has a mass of 1*kg* and is thrown at 5*m*/*s*, what is its kinetic energy?

**Answer:**

Step 1 : Analyse the question to determine what information is provided

- The mass of the rock
*m*= 1*kg* - The speed of the rock
*v*= 5*m*/*s*

These are both in the correct units so we do not have to worry about unit conversions.

Step 2 : Analyse the question to determine what is being asked

- We are asked to find the kinetic energy. From the definition we know that to work out
*E*_{k}, we need to know the mass and the velocity of the object and we are given both of these values.

Step 3 : Substitute and calculate the kinetic energy

To check that the units in the above example are in fact correct:

The units are indeed correct!

Study hint: Checking units is an important cross-check and

you should get into a habit of doing this. If you, for example, finish an exam early then checking the units in your calculations is a very good idea.

#### Worked Example 42 Mixing Units and Kinetic Energy Calculations 1[edit | edit source]

**Question:** If a car has a mass of 900*kg* and is driving at 60*km*/*hr*, what is its kinetic energy?

**Answer:**

Step 1 : Analyse the question to determine what information is provided

- The mass of the car
*m*= 900*kg*

Step 2 : Analyse the question to determine what is being asked

- We are asked to find the kinetic energy.

Step 3 : Substitute and calculate

We know we need the mass and the speed to work out *E*_{k} and we are given both of these
quantities. We thus simply substitute them into the equation for *E*_{k}:

#### Worked Example 43 Mixing Units and Kinetic Energy Calculations 2[edit | edit source]

**Question:** If a bullet has a mass of 150*kg* and is shot at a muzzle velocity of 960*m*/*s*, what is its kinetic energy?

**Answer:**

Step 1 : Analyse the question to determine what information is provided

- We are given the muzzle velocity which is just how fast the bullet leaves the barrel and it is
*v*= 960*m*/*s*.

Step 2 : Analyse the question to determine what is being asked

- We are asked to find the kinetic energy.

Step 3 : Substitute and calculate

We just substitute the mass and velocity (which are known) into the equation for *E*_{k}:

### Potential Energy[edit | edit source]

If you lift an object you have to do work on it. This means that energy is transferred to the object. But where is this energy? This
energy is stored in the object and is called *potential energy*. The reason it is called potential energy is because if we
let go of the object it would move.

Definition:Potential energy is the energy an object has due to its position or state.

As an object raised above the ground falls, its * potential energy* is released and transformed into kinetic energy. The further it falls the faster it moves as more of the stored potential energy
is transferred into kinetic energy. Remember, energy is never created nor destroyed, but merely transformed from one type to another. In this case potential energy is lost but an equal amount of
kinetic energy is gained.

In the example of a falling mass the potential energy is known as *gravitational potential energy* as it is the gravitational force exerted by the earth which causes the mass to accelerate towards the ground. The gravitational field of the earth is what does the work in this case.

Another example is a rubber-band. In order to stretch a rubber-band we have to do work on it. This means we transfer energy to the rubber-band and it gains potential energy. This potential energy is called * elastic potential energy*. Once released, the rubber-band begins to move and elastic potential energy is transferred into kinetic energy.

### Gravitational Potential Energy[edit | edit source]

As we have mentioned, when lifting an object it gains gravitational potential energy. One is free to define any level as corresponding to zero gravitational potential energy. Objects above this level then possess positive potential energy, while those below it have negative potential energy. To avoid negative numbers in a problem, always choose the lowest level as the zero potential mark. The change in gravitational potential energy of an object is given by:

: Change in gravitational potential energy ( J)m: mass of object ( kg)g: acceleration due to gravity ( m.s^{-2}): change in height ( m)

When an object is lifted it gains gravitational potential energy, while it loses gravitational potential energy as it falls.

#### Worked Example 44 Gravitational potential energy[edit | edit source]

**Question:** How much potential energy does a brick with a mass of 1*kg* gain if it is lifted 4*m*.

**Answer:**

Step 1 : Analyse the question to determine what information is provided

- The mass of the brick is
*m*= 1*kg* - The height lifted is

These are in the correct units so we do not have to worry about unit conversions.

Step 2 : Analyse the question to determine what is being asked

- We are asked to find the gain in potential energy of the object.

Step 3 : Identify the type of potential energy involved

Since the block is being lifted we are dealing with gravitational potential energy. To work out , we need to know the mass of the object and the height lifted. As both of these are given, we just substitute them into the equation for .

Step 4 : Substitute and calculate