Circuit Idea/Parallel Voltage Summer
Building fomula: Parallel voltage summer = V-to-I converters + current summer + I-to-V converter.
- 1 A problem: the common ground
- 2 Deriving the simplest current summer from KCL
- 3 Building a parallel voltage summer
- 4 Exploring the circuit
- 5 Do we really need an I-to-V converter?
- 6 Applications
- 7 Parallel versus series summer
- 8 Further reading
A problem: the common ground
Kirchhoff's Voltage Law has already given us an idea how to create the simplest series voltage summer. Unfortunately, it had a lot of disadvantages; maybe, the most crucial of them was the problem of the common ground.
Do you remember? First, we grounded the common point between the input source VIN1 and the load; as a result, the sources VIN2 and VIN3 became flying. Then, we tried to ground the common point between the input sources VIN1 and VIN2; now, the source VIN3 and the load became flying. Finally, we were forced to use only two grounded sources and a differential load.
Only, Kirchhoff has formulated another law - Kirchhoff's Current Law (KCL). Maybe, it can help us to create a perfect voltage summer having no problems with the common ground? Let's try this speculation!
Deriving the simplest current summer from KCL
First, we can apply directly KCL to create a current summer. For this purpose, we have just to connect in parallel the input current sources Ii (let's for concreteness assume again that we have three sources) to the current load LI (Fig. 3). Let's first assume that it is a perfect current load having zero resistance (e.g., just a piece of wire). The output current IOUT flowing through the load is the sum of the input currents: IOUT = IIN1 + IIN2 + IIN3.
We can ask ourselves again, "Only, what is actually the summer here?", "Where is it?" The input current sources and the load are external components; so, the rest (the bare node or the junction point) serves here as a summer!
Wonderful! We have another "ideal" device - the current summer. It is apparent device because there is not actually a device:)!
Building a parallel voltage summer
Only, we want to sum input voltages; so, we have to convert them into currents. For this purpose, we connect voltage-to-current converters between the input voltage sources and the inputs of the current summer (Fig. 4). Also, we need a voltage output; so, we have to connect the opposite current-to-voltage converter at the current summer output. In this way, we have assembled a composed voltage summing circuit:
Let's compare the two viewpoints: From the classical viewpoint, the parallel voltage summer consists of a few resistors; from our viewpoint, it contains voltage-to-current converters, a current summer and a current-to-voltage converter. The use of applying such a system approach is that we see the function of the resistors in the circuit; we see the forest for the tree!
Exploring the circuit
Let's now see how the circuit operates. Attractive voltage bars will help us to visualize the invisible voltages and voltage drops (Fig. 5); current loops will show us where the currents flow (remember: every current returns where it has begun flowing).
The input voltage sources VIN produce voltages, the resistors RIN convert them into currents, the junction point sums the currents and finally, the resistor R converts back the current sum into an output voltage VOUT.
Only, the output voltage introduces an error because it subtracts from the input voltages. Now, the effective voltages VR1, VR2 and VR3 create the currents instead the whole input voltages VIN1, VIN2 and VIN3:
IIN1 = (VIN1 - VOUT)/R1 = VR1/R1
IIN2 = (VIN2 - VOUT)/R2 = VR2/R2
IIN3 = (VIN3 - VOUT)/R3 = VR3/R3
How do we remove the error?
Do we really need an I-to-V converter?
Maybe, you have already noted the contradictory role of the resistor R.
In order not to disturb the input sources (see above), we want the resistance R to be as small as possible (preferably R = 0). As a result, the input voltage-to-current converters become each other independent; only, the output voltage decreases:( We will use this technique later when we build an active parallel voltage summer.
But why do not we increase the resistance R up to infinity (i.e., just to remove the resistor R)? In this case, the input voltage-to-current converters become each other absolutely dependent but we obtain a maximal output voltage. We can use this solution when the load has an infinite internal resistance (e.g., when we have buffered the passive summer by a non-inverting amplifier).
Only, there is a sound reason to connect the "unnecessary" resistor R - it can add the input coefficients up to 1 (see more explanations). We will use this technique below to build a simple digital-to-analog converter.
The parallel voltage summer exists in many analog circuits considered in electronics books; only, authors do not discern and do not pay attention to it. As a result, it is presented rather implicitly than manifestly. In this section, we will do our best to show its presence in various electronic circuits. This famous circuit deserves our attention.
Op-amp inverting voltage summer
Maybe, the most important application of the passive summer is building an op-amp active summer. Only, what is the idea behind such an op-amp inverting summing circuit (Fig. 7)?
From the classical viewpoint, an op-amp inverting summer consists of input resistors Ri, a negative feedback resistor R and an op-amp. Only, thinking of the active circuit in this way we can't discern the basic idea behind it; we do not see the forest for the tree.
From our fresh viewpoint, an op-amp inverting summer consists of a passive parallel voltage summer and an op-amp:
More precisely speaking, an n-input op-amp inverting summer needs an (n+1)-input passive parallel voltage summer. For example, in order to build a 3-input op-amp inverting summer (our case) we have to add an additional fourth input IN4. A properly supplied op-amp serves as an additional input voltage source that adjusts its output voltage VOUT (the "input" voltage VIN4) so that to zero the passive summer's output voltage VA (the virtual ground). As a result, the op-amp's output voltage represents the sum of the input voltages VIN. Let's repeat again:
We (i.e., the op-amp) introduce(s) an additional "compensating" input and make its voltage equal to the sum of the rest "true" input voltages. Then, we abandon the "genuine" summer's output voltage VA (now, it serves only as an indication of an equilibrium) and begin using the compensating voltage VIN4 as an output.
What is a digital-to-analog converter (DAC)? It is just a circuit that materializes an abstract digit (most frequently, converting it into a voltage). A parallel voltage summer having binary-weighted inputs can do this work.
In this example (Fig. 8), a 3-bit digital device drives the DAC. Here we suppose that the high voltage levels of the three digital outputs are relatively equal; this voltage serves as a reference VREF. The output voltage is:
VOUT = 0.1 x b0 x VREF + 0.2 x b1 x VREF + 0.4 x b2 x VREF
For example, you can connect such a simple DAC to the parallel computer port (such as a printer port).
The resistor R is absolutely necessary in this application; it adds the sum of the input coefficients up to 1 (according to Daisy's theorem). You can use the nice Brandy's formula to calculate the resistances.
Another popular application of the parallel summing circuit is audio mixing of analog signals from a few voltage sources.
Note again that the parallel summer not just sums the signals; it also attenuates them. In this case, this feature is useful.
Parallel versus series summer
We can do a few remarks about the parallel voltage summing circuit in comparison with the series one.
• The output voltage of the parallel voltage summer is a weighted sum of the input voltages; the output voltage of the series voltage summer is a sum of the whole input voltages.
• The input sources and the load of the parallel voltage summer are grounded; only two devices (sources or a source and a load) of the series configuration can be grounded, the rest remain flying.