Basic Algebra/Introduction to Basic Algebra Ideas/Chapter Test

Section A (5 marks)

Evaluate the following expressions.

1

$24\div 6-7=$

2

$(5+3)\times 6=$

3

${\frac {16+14}{5}}-3=$

4

${\frac {36}{4-(-2)}}+5=$

5

$\left({\frac {2\times 27}{9}}\right)^{2}=$

Section B (5 marks)

Evaluate the following expressions.

6

$9+3^{2}=$

7

$3+{\frac {20}{2^{2}}}=$

8

${\frac {2(3+4)}{94^{0}}}=$

9

$20-2\left({\frac {96}{4^{2}}}\right)=$

10

$-4+5\left({\frac {56+7}{3^{2}}}\right)-1=$

Section C (5 marks)

Evaluate the following expressions when $w=4$, $x=5$, $y=6$ and $z=7$.

11

$3x+2y+z=$

12

${\frac {w^{2}}{y+2}}+2z=$

13

$2\left({\frac {x^{2}+3}{w}}\right)-(2y-z)=$

14

$(6-3)\left({\frac {2w-x}{z-4}}\right)+(3y-4)=$

15

$3^{2}(2w^{0})\left({\frac {wx}{y-2}}\right)-z=$

Section D (6 marks)

Evaluate the value of $x$ in the following equations with the given value of $y$.

16 $4x+3y=18$ (given $y=2$)

$x=$

17 ${\frac {2x}{y+1}}+4=20$ (given $y=3$)

$x=$

18 $2\left({\frac {2x-2}{y-3}}\right)+8=6^{2}$ (given $y=7$)

$x=$

19 $3^{3}+2^{0}+3x-2y\left({\frac {18}{2}}\right)=97$ (given $y=3$)

$x=$

20 $[5(2x-3)]^{2}=y+6$ (given $y=19$)

$x\in \{$ , $\}$