Basic Algebra/Introduction to Basic Algebra Ideas/Chapter Test

Jump to: navigation, search

Please post your test problems this way:

• Problem:(answer,level of difficulty(easy, medium, hard))
• Example 2x=6: (x=3,easy)
1. (5 + x)^2 where x=4 (easy)
2. 3*3+4 (easy)
3. 2x–(2x+3) where x=.5 (medium)

Section A (5 marks)

Evaluate the following expressions.

1. ${\displaystyle 24\div 6-7=}$
2. ${\displaystyle (5+3)\times 6=}$
3. ${\displaystyle {\frac {16+14}{5}}-3=}$
4. ${\displaystyle {\frac {36}{4-(-2)}}+5=}$
5. ${\displaystyle ({\frac {2\times 27}{9}})^{2}=}$

Section B (5 marks)

Evaluate the following expressions.

1. ${\displaystyle 9+3^{2}=}$
2. ${\displaystyle 3+{\frac {20}{2^{2}}}=}$
3. ${\displaystyle {\frac {2(3+4)}{)}}{94^{0}}=}$
4. ${\displaystyle 20-2({\frac {96}{4^{2}}})=}$
5. ${\displaystyle -4+5({\frac {56+7}{3^{2}}})-1=}$

Section C (5 marks)

Evaluate the following expressions when ${\displaystyle w=4}$, ${\displaystyle x=5}$, ${\displaystyle y=6}$ and ${\displaystyle z=7}$.

1. ${\displaystyle 3x+2y+z=}$
2. ${\displaystyle {\frac {w^{2}}{y+2}}+2z=}$
3. ${\displaystyle 2({\frac {x^{2}+3}{w}})-(2y-z)=}$
4. ${\displaystyle (6-3)({\frac {2w-x}{z-4}})+(3y-4)=}$
5. ${\displaystyle 3^{2}(2w^{0})({\frac {wx}{y-2}})-z=}$

Section D (5 marks)

Evaluate the value of ${\displaystyle x}$ in the following equations with the given value of ${\displaystyle y}$.

1. ${\displaystyle 4x+3y=18}$ (given ${\displaystyle y=2}$)
2. ${\displaystyle {\frac {2x}{y+1}}+4=20}$ (given ${\displaystyle y=3}$)
3. ${\displaystyle 2({\frac {2x-2}{y-3}}+8=6^{2}}$ (given ${\displaystyle y=7}$)
4. ${\displaystyle 3^{3}+2^{0}+3x-2y({\frac {18}{2}})=97}$ (given ${\displaystyle y=3}$)
5. ${\displaystyle [5(2x-3)]^{2}=y+6}$ (given ${\displaystyle y=19}$)
 « Basic Algebra Chapter Test » Chapter Review Working with Numbers - Integers and the Number Line