${\displaystyle x={\frac {-b+{\sqrt {b^{2}-4ac}}}{2a}}}$ OR ${\displaystyle x={\frac {-b-{\sqrt {b^{2}-4ac}}}{2a}}}$
A quadratic function has a "vertex" or "turning point", which is the point where the function has either a maximum or minimum value. If a is greater than zero, then there will be a minimum and the curve will be concave. If a is less than zero, then there will be a maximum and the curve will be convex. If a = 0, then we have a linear function rather than a quadratic function.The x-coordinate of the vertex is ${\displaystyle x=-{\frac {b}{2a}}}$ The y-coordinate of the vertex is ${\displaystyle F(-{\frac {b}{2a}})}$