A-level Physics (Advancing Physics)/Graphs/Worked Solutions
At this point, the graph is a straight line. So:
2. What is the velocity at 12 seconds?
Approximately, there is a rough straight line at this point. The object is travelling towards home 2 ms−1 each second (look at the previous second, for example). So, its velocity is -2 ms−1.
Distance travelled is equal to the area under the graph. Between 7 and 9 seconds, this is the shaded area of the graph. So, calculate the area of the triangle:
4. What is the object's acceleration at 8 seconds?
There is a straight line between 7 and 9 seconds which we can use to answer this question. The acceleration is equal to the gradient of the graph, so:
5. A car travels at 10ms−1 for 5 minutes in a straight line, and then returns to its original location over the next 4 minutes, travelling at a constant velocity. Draw a distance-time graph showing the distance the car has travelled from its original location.
10ms−1 = 600 metres / minute.
6. Draw the velocity-time graph for the above situation.
The velocity from 0-5s is 10ms−1. The velocity from 5-9s is:
7. The velocity of a ball is related to the time since it was thrown by the equation . How far has the ball travelled after 2 seconds?