# A-level Physics (Advancing Physics)/Cloud Chambers and Mass Spectrometers/Worked Solutions

Charge of electron = -1.6 x 10-19C

Mass of electron = 9.11 x 10-31kg

u = 1.66 x 10-27kg

1. An electron enters a cloud chamber, passing into a 0.1T magnetic field. The initial curvature (the reciprocal of its radius) of its path is 100m-1. At what speed was it moving when it entered the magnetic field?

${\displaystyle r={\frac {mv}{qB}}}$

${\displaystyle v={\frac {qBr}{m}}={\frac {1.6\times 10^{-19}\times 0.1\times 0.01}{9.11\times 10^{-31}}}=1.76\times 10^{8}{\mbox{ ms}}^{-1}=0.585c}$

This is too close to the speed of light to ignore special relativity, however we just did.

2. The electron spirals inwards in a clockwise direction, as show in the diagram on the right. What would the path of a positron, moving with an identical speed, look like?

3. Using a 2T magnetic field, what electric field strength must be used to get a velocity selector to select only particles which are moving at 100ms-1?

${\displaystyle v={\frac {E}{B}}}$

${\displaystyle E=Bv=2\times 100=200{\mbox{ Vm}}^{-1}}$

4. Some uranium (atomic number 92) ions (charge +3e) of various isotopes are put through the velocity selector described in question 3. They then enter an 0.00002T uniform magnetic field. What radius of circular motion would uranium-235 have?

${\displaystyle {\frac {m}{q}}={\frac {rBB_{selector}}{E_{selector}}}}$

${\displaystyle {\frac {235\times 1.66\times 10^{-27}}{3\times 1.6\times 10^{-19}}}=r\times {\frac {2\times 0.00002}{200}}=0.0000002r}$

${\displaystyle r={\frac {235\times 1.66\times 10^{-27}}{0.0000002\times 3\times 1.6\times 10^{-19}}}=4.06{\mbox{ m}}}$