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Fundamentals of Data Representation: Unsigned binary arithmetic

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PAPER 2 - ⇑ Fundamentals of data representation ⇑

← Unsigned binary Unsigned binary arithmetic Twos complement →


You should be comfortable with adding, subtracting and multiplying in decimal. Computers need to do the same in binary, and you need to know it for the exam!

Addition

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Let's look at an example of adding in decimal:

 25
+43
---
 68

This is pretty simple, we just add up each column, but what happens if we have can't fit the result in one column. We'll have to use a carry bit:

 98
+57
---
155
11

Hopefully you're good with that. Now let's take a look at how it's done in binary with a very quick example, with a check in denary:

 01010 (1010)
+00101 (510)
------
 01111 (1510)

This seems pretty straight forward, but what happens when we have a carry bit? Well pretty much the same as in denary:

 01011 (1110)
+00001 (110)
------
 01100 (1210)
   11
How carry bits are used in binary addition
Exercise: Binary Addition

1010 + 0001

Answer:

 1010
+0001
 ----
 1011

01001001 + 00110000

Answer:

 01001001 
+00110000
 --------
 01111001

01010100 + 00110000

Answer:

 01010100 
+00110000
 --------
 10000100

01001010 + 00011011

Answer:

 01001010 
+00011011
 --------
 01100101

01111101 + 00011001

Answer:

 01111101 
+00011001
 --------
 10010110

00011111 + 00011111

Answer:

 00011111 
+00011111
 --------
 00111110

10101010 + 01110000

Answer:

 10101010 
+01110000
 --------
100011010
Note we have some overflow, this will come in useful when doing subtraction

Multiplication

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You should hopefully have learnt how to multiply numbers together in decimal when you were at primary school. Let's recap:

 12
x 4
 --
  8   =  4*2
 40   =  4*10–48

And with a more complicated example:

 12
x14–8   =  4 * 2
 40   =  4 * 10
 20   =  10* 2
100   =  10* 10–168

The same principle applies with binary. Let's take a look at an example:

 101
x 10
----
   0   =  0 * 101
1010   = 10 * 101 [or in denary 2 * 5 = 10]

Let's try a more complicated example:

   1011 [11]
  x 111 [7]
  ----
   1011 =   1 * 1011 
  10110 =  10 * 1011
 101100 = 100 * 1011
 ------ now add them together
1001101 = [77 double check with the decimal earlier]
Exercise: Binary Multiplication

101 * 10

Answer:

 101
x 10
----
1010

11 * 11

Answer:

  11
x 11
----
  11
 110
----
1001

1011 * 101

Answer:

  1011 
x  101
------
  1011
101100
------
110111

1111 * 111

Answer:

    1111  = 15
  x  111  = 7
  ------
    1111
   11110
  111100
  ------
 1101001 = 105

If you multiply a binary number by 2, how many spaces does it move to the left?

Answer:

1

If you multiply a binary number by 16, how many spaces does it move to the left?

Answer:

4 (as 2^4 = 16)

This is a short cut for multiplication in computers, and it uses machine code shift instructions to do this. Don't worry you don't need to know them for this syllabus

Extension: Bit Shifts

If you look at the binary representations of the following numbers you may notice something peculiar:

0001 = 1
0010 = 2
0100 = 4
1000 = 8

Each time we shift the number one space to the left, the value of the number doubles. This doesn't only work for one bit, take a look at this more complicated example.

0001 0101 = 21
0010 1010 = 42

Again, one shift to the left and the number has doubled. On the other hand, one shift to the right halves the value.

Computers are notoriously bad at doing multiplication and division, it takes lots of CPU time and can really slow your code down. To try and get past this problem computers can shift the values in registers and as long as multiplication or division is by powers of 2, then the CPU time is reduced as the action takes only one line of Machine Code. There are several types of shifts that processors can perform:

  • Logical Shift

Shifting either left or right, you add a 0 on the empty end.

  • Arithmetic Shift

You maintain the sign bit of the number being shifted.

Please note the Logical shift example is also an example of an arithmetic shift as the sign remains the same. You'll find out about sign bits when learning about two's complement

  • Circular Shift

The bit that is pushed off one end appears on the other