Haskell/do notation

From Wikibooks, open books for an open world
< Haskell(Redirected from Haskell/do Notation)
Jump to: navigation, search

Using do blocks as an alternative monad syntax was first introduced way back in the Simple input and output chapter. There, we used do to sequence input/output operations, but we hadn't introduced monads yet. Now, we can see that IO is yet another monad.

Since the following examples all involve IO, we will refer to the computations/monadic values as actions (as we did in the earlier parts of the book). Of course, do works with any monad; there is nothing specific about IO in how it works.

Translating the then operator[edit]

The (>>) (then) operator works almost identically in do notation and in unsugared code. For example, suppose we have a chain of actions like the following one:

putStr "Hello" >> 
putStr " " >> 
putStr "world!" >> 
putStr "\n"

We can rewrite that in do notation as follows:

do { putStr "Hello"
   ; putStr " "
   ; putStr "world!"
   ; putStr "\n" }

(using the optional braces and semicolons explicitly, for clarity). This sequence of instructions nearly matches that in any imperative language. In Haskell, we can chain any actions as long as all of them are in the same monad. In the context of the IO monad, the actions include writing to a file, opening a network connection, or asking the user for an input.

Here's the step-by-step translation of do notation to unsugared Haskell code:

do { action1           -- by monad laws equivalent to:  do { action1 
   ; action2           --                                  ; do { action2
   ; action3 }         --                                       ; action3 } }


action1 >>
do { action2
   ; action3 }

and so on, until the do block is empty.

Translating the bind operator[edit]

The bind operator (>>=) is a bit more difficult to translate from and to the do notation. (>>=) passes a value, namely the result of an action or function, downstream in the binding sequence. do notation assigns a variable name to the passed value using the <-.

do { x1 <- action1
   ; x2 <- action2
   ; mk_action3 x1 x2 }

The curly braces and the semicolons are optional if every line of code is indented to line up equally (NB: beware the mixing of tabs and spaces in that case; with the explicit curly braces and semicolons indentation plays no part and there's no danger).

x1 and x2 are the results of action1 and action2. If, for instance, action1 is an IO Integer then x1 will be bound to an Integer value. The two bound values in this example are passed as arguments to mk_action3, which creates a third action. The do block is broadly equivalent to the following vanilla Haskell snippet:

action1 >>= (\ x1 -> action2 >>= (\ x2 -> mk_action3 x1 x2 ))

The second argument of the first (leftmost) bind operator (>>=) is a function (lambda expression) specifying what to do with the result of the action passed as the bind's first argument. Thus, chains of lambdas pass the results downstream. The parentheses could be omitted, because a lambda expression extends as far as possible. x1 is still in scope at the point we call the final action maker mk_action3. We can rewrite the chain of lambdas more legibly by using separate lines and indentation:

    (\ x1 -> action2
         (\ x2 -> mk_action3 x1 x2 ))

That shows the scope of each lambda function clearly. To group things more like the do notation, we could show it like this:

action1 >>= (\ x1 ->
  action2 >>= (\ x2 ->
    mk_action3 x1 x2 ))

These presentation differences are only a matter of assisting readability.[1]

The fail method[edit]

Above, we said the snippet with lambdas was "broadly equivalent" to the do block. The translation is not exact because the do notation adds special handling of pattern match failures. When placed at the left of either <- or ->, x1 and x2 are patterns being matched. Therefore, if action1 returned a Maybe Integer we could write a do block like this...

do { Just x1 <- action1
   ; x2      <- action2
   ; mk_action3 x1 x2 }

...and x1 be an Integer. In such a case, what happens if action1 returns Nothing? Ordinarily, the program would crash with an non-exhaustive patterns error, just like the one we get when calling head on an empty list. With do notation, however, failures are handled with the fail method for the relevant monad. The do block above translates to:

action1 >>= f
where f (Just x1) = do { x2 <- action2
                       ; mk_action3 x1 x2 }
      f _         = fail "..." -- A compiler-generated message.

What fail actually does depends on the monad instance. Though it will often rethrow the pattern matching error, monads that incorporate some sort of error handling may deal with the failure in their own specific ways. For instance, Maybe has fail _ = Nothing; analogously, for the list monad fail _ = [].[2]

The fail method is an artifact of do notation. Rather than calling fail directly, you should rely on automatic handling of pattern match failures whenever you are sure that fail will do something sensible for the monad you are using.

Example: user-interactive program[edit]


We are going to interact with the user, so we will use putStr and getLine alternately. To avoid unexpected results in the output, we must disable output buffering when importing System.IO. To do this, put hSetBuffering stdout NoBuffering at the top of your code. To handle this otherwise, you would explicitly flush the output buffer before each interaction with the user (namely a getLine) using hFlush stdout. If you are testing this code with ghci, you don't have such problems.

Consider this simple program that asks the user for their first and last names:

nameDo :: IO ()
nameDo = do putStr "What is your first name? "
            first <- getLine
            putStr "And your last name? "
            last <- getLine
            let full = first ++ " " ++ last
            putStrLn ("Pleased to meet you, " ++ full ++ "!")

A possible translation into vanilla monadic code:

nameLambda :: IO ()
nameLambda = putStr "What is your first name? " >>
             getLine >>= \ first ->
             putStr "And your last name? " >>
             getLine >>= \ last ->
             let full = first ++ " " ++ last
             in putStrLn ("Pleased to meet you, " ++ full ++ "!")

In cases like this, where we just want to chain several actions, the imperative style of do notation feels natural and convenient. In comparison, monadic code with explicit binds and lambdas is something of an acquired taste.

Notice that the first example above includes a let statement in the do block. The de-sugared version is simply a regular let expression where the in part is whatever follows from the do syntax.

Returning values[edit]

The last statement in do notation is the overall result of the do block. In the previous example, the result was of the type IO (), i.e. an empty value in the IO monad.

Suppose that we want to rewrite the example but return an IO String with the acquired name. All we need to do is add a return:

nameReturn :: IO String
nameReturn = do putStr "What is your first name? "
                first <- getLine
                putStr "And your last name? "
                last <- getLine
                let full = first ++ " " ++ last
                putStrLn ("Pleased to meet you, " ++ full ++ "!")
                return full

This example will "return" the full name as a string inside the IO monad, which can then be utilized downstream elsewhere:

greetAndSeeYou :: IO ()
greetAndSeeYou = do name <- nameReturn
                    putStrLn ("See you, " ++ name ++ "!")

Here, nameReturn will be run and the returned result (called "full" in the nameReturn function) will be assigned to the variable "name" in our new function. The greeting part of nameReturn will be printed to the screen because that is part of the calculation process. Then, the additional "see you" message will print as well, and the final returned value is back to being IO ().

If you know imperative languages like C, you might think return in Haskell matches return elsewhere. A small variation on the example will dispel that impression:

nameReturnAndCarryOn = do putStr "What is your first name? "
                          first <- getLine
                          putStr "And your last name? "
                          last <- getLine
                          let full = first++" "++last
                          putStrLn ("Pleased to meet you, "++full++"!")
                          return full
                          putStrLn "I am not finished yet!"

The string in the extra line will be printed out because return is not a final statement interrupting the flow (as it would be in C and other languages). Indeed, the type of nameReturnAndCarryOn is IO (), — the type of the final putStrLn action. After the function is called, the IO String created by the return full will disappear without a trace.

Just sugar[edit]

As a syntactical convenience, do notation does not add anything essential, but it is often preferable for clarity and style. However, do is not needed for a single action, at all. The Haskell "Hello world" is simply:

main = putStrLn "Hello world!"

Snippets like this one are totally redundant:

fooRedundant = do { x <- bar
                  ; return x }

Thanks to the monad laws, we can write it simply as

foo = do { bar }   -- which is, further,
foo = bar

A subtle but crucial point relates to function composition: As we already know, the greetAndSeeYou action in the section just above could be rewritten as:

greetAndSeeYou :: IO ()
greetAndSeeYou = nameReturn >>= (\ name -> putStrLn ("See you, " ++ name ++ "!"))

While you might find the lambda a little unsightly, suppose we had a printSeeYou function defined elsewhere:

printSeeYou :: String -> IO ()
printSeeYou name = putStrLn ("See you, " ++ name ++ "!")

Now, we can have a clean function definition with neither lambdas or do:

greetAndSeeYou :: IO ()
greetAndSeeYou = nameReturn >>= printSeeYou

Or, if we have a non-monadic seeYou function:

seeYou :: String -> String
seeYou name = "See you, " ++ name ++ "!"

Then we can write:

-- Reminder: fmap f m  ==  m >>= (return . f)  ==  liftM f m
greetAndSeeYou :: IO ()
greetAndSeeYou = fmap seeYou nameReturn >>= putStrLn

Keep this last example with fmap in mind; we will soon return to using non-monadic functions in monadic code, and fmap will be useful there.


  1. Actually, the indentation isn't needed in this case. This is equally valid:
    action1 >>= \ x1 ->
    action2 >>= \ x2 ->
    action3 x1 x2

    Of course, we could use even more indentation if we wanted. Here's an extreme example:


    While that indention is certainly overkill, it could be worse:

      >>= \
          -> action2 >>=
              x2 ->
                action3 x1

    That is valid Haskell but is baffling to read; so please don't ever write like that. Write your code with consistent and meaningful groupings.

  2. This explains why, as we pointed out in the "Pattern matching" chapter, pattern matching failures in list comprehensions are silently ignored.