# Turing/Solution 1

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< Turing

var n : int %User input var ctr : int := 0 %Counter variable var gotit : boolean %Stores if fractorial is found get n loop ctr := 0 %ctr is NEVER actually used as zero, since that would cause a division by 0 error. loop gotit := true %Initially assume that fractorial has been found, and change to false if found otherwise ctr += n %Increase counter by n for i : 1 .. n %Try n/1, n/2, n/3... until n/i. If all are whole numbers, then answer has been found if ctr / i not= ctr div i then gotit := false end if end for exit when gotit = true end loop if gotit = true then put "Fractorial (", n, ") = ", ctr exit end if end loop

While you might try ctr += 1 initially, it will quickly become evident that this is too slow. Through logical reasoning and some experimentation, you should be able to discover that the fractorial of n is a multiple of n.