Trigonometry/Multiple-Angle and Product-to-sum Formulas

From Wikibooks, the open-content textbooks collection

< Trigonometry
Jump to: navigation, search


[edit] Proofs for Double Angle Formulas

[edit] Using the Sum and Difference Identities

Recall that:
 \displaystyle\cos(a + b) = \cos(a)\cos(b) - \sin(a)\sin(b)

Using a = b in the above formula yields:

   \displaystyle\cos(2a) = \cos(a + a) = \cos(a)\cos(a) - \sin(a)\sin(a) = \cos^2(a) - \sin^2(a) 

From the last (rightmost) term, two more identities may be derived. One containing only a sine:

   \displaystyle\cos(2a) = \cos^2(a) - \sin^2(a) = \cos^2(a) - \sin^2(a) + 0 = \cos^2(a) - \sin^2(a) + [\sin^2(a) - \sin^2(a)] = [\cos^2(a) + \sin^2(a)] - 2\sin^2(a) = 1 - 2\sin^2(a) 

And one containing only a cosine:

   \displaystyle\cos(2a) = \cos^2(a) - \sin^2(a) = \cos^2(a) - \sin^2(a) + 0 = \cos^2(a) - \sin^2(a) + [\cos^2(a) - \cos^2(a)] = 2\cos^2(a) - [\cos^2(a) + \sin^2(a)] = 2\cos^2(a) - 1 


\displaystyle\sin(a + b) = \sin(a)\cos(b) + \sin(b)\cos(a) ; a = b for sin(2a)

  \displaystyle\sin(a)\cos(a) + \sin(a)\cos(a) = 2\cos(a)\sin(a) = \sin(2a)

Next Page: Law of Sines | Previous Page: Sum and Difference Formulas

Home: Trigonometry

Personal tools
Create a book
  • Add wiki page
  • Collections help