Practical Electronics/Operating amplifiers

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[edit] Intro

Op Amp is short hand of Operational Amplifier . A tool used in amplifying the difference of two input voltages

Vo = A (V2 - V1)

Op Amp has an Integrated Circuit of electronic coponents inside a chip of 8 pins

Operational Amplifier IC Chip
Pin Useage
1 Offset Null
2 Inverted Input
3 Non-Inverted Input
4 -V Supply
5 No use
6 Output
7 +V Supply
8 No use


Op Amp 's symbol op-amp

  • V+: non-inverting input
  • V: inverting input
  • Vout: output
  • VS+: positive power supply
  • VS−: negative power supply

Op Amp amplify AC signal or AC Voltage better than bipolar junction transistor

[edit] Op Amp Functions

[edit] Voltage Difference Amplifier

From above

V0 = A (V2 - V1)

With two voltages V1 và V2 ≠ 0

If V2 = V1 , V0 = 0 . No output voltage
If V2 > V1 , V0 > 0 . Non-Inverting Amplifier
Nếu V2 < V1 , V0 < 0 . Inverting Amplifier

With one voltage is grounded

If V2 = 0 , V0 = -A V1 . Inverting Amplifier
If V1 = 0 , V0 = A V2 . Non-Inverting Amplifier

[edit] Voltage Comparator

V2 > V1 , V0 = +Vss
V2 < V1 , V0 = -Vss
V2 = V1 , V0 = 0

[edit] Linear Configurations

[edit] Differential amplifier

Differential amplifier
 V_\mathrm{out} = V_2 \left( { \left( R_\mathrm{f} + R_1 \right) R_\mathrm{g} \over \left( R_\mathrm{g} + R_2 \right) R_1} \right) - V_1 \left( {R_\mathrm{f} \over R_1} \right)
  • Differential Zin (between the two input pins) = R1 + R2

[edit] Voltage Difference Amplifier

Whenever R1 = R2 and Rf = Rg,

 V_\mathrm{out} = {R_\mathrm{f} \over R_1} \left( V_2 - V_1 \right)

[edit] Voltage Difference

When R1 = Rf and R2 = Rg (including previous conditions, so that R1 = R2 = Rf = Rg):

 V_\mathrm{out} =  V_2 - V_1 \,\!

[edit] Inverting Amplifier

Inverting amplifier
 V_\mathrm{out} = - V_\mathrm{in} \left( {R_f \over R_1} \right)

Inverting Amplification is dictated by the ratio of the two resistors

[edit] Non-Inverting Amplifier

Non-inverting amplifier
 V_\mathrm{out} = V_\mathrm{in} \left( 1 + {R_2 \over R_1} \right)

Non-Inverting Amplification is dictated by the ratio of the two resistors plus one

[edit] Voltage Follower

Voltage follower

From Non-Inverting Amplifier's formula. If the resistors has the same value of resistance then output voltage is exactly equal to the input voltage

 V_\mathrm{out} = V_\mathrm{in} \!\

From Inverting Amplifier's formula. If the resistors has the same value of resistance then output voltage is exactly equal to the input voltage and inverted

 V_\mathrm{out} = - V_\mathrm{in} \!\

[edit] Summing amplifier

Summing amplifier
 V_\mathrm{out} = - R_\mathrm{f} \left( { V_1 \over  R_1 } + { V_2 \over R_2 } + \cdots + {V_n \over R_n} \right)

When R_1 = R_2 = \cdots = R_n, and Rf independent

 V_\mathrm{out} = - \left( {R_\mathrm{f} \over R_1} \right) (V_1 + V_2 + \cdots + V_n ) \!\

When R_1 = R_2 = \cdots = R_n = R_\mathrm{f}

 V_\mathrm{out} = - ( V_1 + V_2 + \cdots + V_n ) \!\

[edit] Integrator

Integrating amplifier

Integrates the (inverted) signal over time

 V_\mathrm{out} = \int_0^t - {V_\mathrm{in} \over RC} \, dt + V_\mathrm{initial}

(where Vin and Vout are functions of time, Vinitial is the output voltage of the integrator at time t = 0.)


[edit] Differentiator

Differentiating amplifier

Differentiates the (inverted) signal over time.

The name "differentiator" should not be confused with the "differential amplifier", also shown on this page.

V_\mathrm{out} = - RC \left( {dV_\mathrm{in} \over dt} \right)

(where Vin and Vout are functions of time)


[edit] Comparator

Comparator
  •  V_\mathrm{out} = \left\{\begin{matrix} V_\mathrm{S+} & V_1 > V_2 \\ V_\mathrm{S-} & V_1 < V_2 \end{matrix}\right.

Từ V0 = A (V2 - V1)

  • Vo = 0 khi V2 = V1
  • Vo > 0 khi V2 > V1
Vo = Vss
  • Vo < 0 khi V2 < V1
Vo = V-ss

When two input voltages equal. The output voltage is zero . When the two input voltages different and if one is greater than or less than the other

  1. Vo = Vss khi V2 > V1
  2. Vo = V-ss khi V2 < V1

[edit] Instrumentation amplifier

Instrumentation amplifier


Combines very high input impedance, high common-mode rejection, low DC offset, and other properties used in making very accurate, low-noise measurements

[edit] Schmitt trigger

Schmitt trigger

A comparator with hysteresis

Hysteresis from \frac{-R_1}{R_2}V_{sat} to \frac{R_1}{R_2}V_{sat}.

[edit] Gyrator

Inductance gyrator
L = RLRC

[edit] Zero level detector

Voltage divider reference

  • Zener sets reference voltage

[edit] Negative impedance converter (NIC)

Negative impedance converter


Creates a resistor having a negative value for any signal generator

  • In this case, the ratio between the input voltage and the input current (thus the input resistance) is given by:
R_\mathrm{in} = - R_3 \frac{R_1}{R_2}

[edit] Non-linear configurations

[edit] Chỉnh Lưu

Super diode

Behaves like an ideal diode for the load, which is here represented by a generic resistor RL.

  • This basic configuration has some limitations. For more information and to know the configuration that is actually used, see the main article.

[edit] Peak detector

Peak detector

When the switch is closed, the output goes to zero volts. When the switch is opened for a certain time interval, the capacitor will charge to the maximum input voltage attained during that time interval.

The charging time of the capacitor must be much shorter than the period of the highest appreciable frequency component of the input voltage.

[edit] Logarithmic output

Logarithmic configuration
  • The relationship between the input voltage vin and the output voltage vout is given by:
v_\mathrm{out} = -V_{\gamma} \ln \left( \frac{v_\mathrm{in}}{I_\mathrm{S} \cdot R} \right)

where IS is the saturation current.

  • If the operational amplifier is considered ideal, the negative pin is virtually grounded, so the current flowing into the resistor from the source (and thus through the diode to the output, since the op-amp inputs draw no current) is:
\frac{v_\mathrm{in}}{R} = I_\mathrm{R} = I_\mathrm{D}

where ID is the current through the diode. As known, the relationship between the current and the voltage for a diode is:

I_\mathrm{D} = I_\mathrm{S} \left( e^{\frac{V_\mathrm{D}}{V_{\gamma}}} - 1 \right)

This, when the voltage is greater than zero, can be approximated by:

I_\mathrm{D} \simeq I_\mathrm{S} e^{V_\mathrm{D} \over V_{\gamma}}

Putting these two formulae together and considering that the output voltage Vout is the inverse of the voltage across the diode VD, the relationship is proven.

Note that this implementation does not consider temperature stability and other non-ideal effects.

[edit] Exponential output

Exponential configuration
  • The relationship between the input voltage vin and the output voltage vout is given by:
v_\mathrm{out} = - R I_\mathrm{S} e^{v_\mathrm{in} \over V_{\gamma}}

where IS is the saturation current.

  • Considering the operational amplifier ideal, then the negative pin is virtually grounded, so the current through the diode is given by:
I_\mathrm{D} = I_\mathrm{S} \left( e^{\frac{V_\mathrm{D}}{V_{\gamma}}} - 1 \right)

when the voltage is greater than zero, it can be approximated by:

I_\mathrm{D} \simeq I_\mathrm{S} e^{V_\mathrm{D} \over V_{\gamma}}

The output voltage is given by:

v_\mathrm{out} = -R I_\mathrm{D}\,
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