File:Calculus graphing exercise 2.png
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Summary
| Description |
English: Function that satisfies the following conditions: |
| Date | |
| Source | Own work |
| Author | Paul Breen |
![{\displaystyle f{\mbox{ has domain }}[-1,1],\;f(-1)=-1,\;f(-{\frac {1}{2}})=-2,\;f'(-{\frac {1}{2}})=0,\;f''(x)>0{\mbox{ on }}(-1,1)}](https://wikimedia.org/api/rest_v1/media/math/render/svg/c0510fb43f1d1d920e02728b009d47ddc0a882e6)
Licensing
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This file is made available under the Creative Commons CC0 1.0 Universal Public Domain Dedication. |
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File history
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| Date/Time | Thumbnail | Dimensions | User | Comment | |
|---|---|---|---|---|---|
| current | 15:02, 21 May 2011 | | 429 × 254 (3 KB) | Greenbreen | {{Information |Description ={{en|1=Function that satisfies the following conditions:<br/> <math>f \mbox{ has domain } [-1,1], \; f(-1) = -1, \; f(-\frac{1}{2}) = -2,\; f'(-\frac{1}{2}) = 0,\; f''(x)>0 \mbox{ on } (-1,1) </math>}} |Source =My ow |
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