Differential Equations/Homogeneous x and y

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Not to be confused with homogeneous equations, an equation homogeneous in x and y of degree n is an equation of the form

F(x,y,y')=0

Such that

anF(x,y,y') = F(ax,ay,y').

Then the equation can take the form

x^nF(1,\frac{y}{x},y')=0

Which is essentially another in the form

x^nF(\frac{y}{x},y')=0.

If we can solve this equation for y', then we can easily use the substitution method mentioned earlier to solve this equation. Suppose, however, that it is more easily solved for \frac{y}{x},

\frac{y}{x}=f(y')

So that

y = xf(y').

We can differentiate this to get

y'=f(y')+xf'(y')y

Then re-arranging things,

\frac{dx}{x}=\frac{f'(y')}{y'-f(y')}dy'

So that upon integrating,

ln(x)=\int \frac{f'(y')}{y'-f(y')}dy'+C

We get

x=Ce^{\int \frac{f'(y')}{y'-f(y')}dy'}

Thus, if we can eliminate y' between two simultaneous equations

y = xf(y')

and

x=Ce^{\int \frac{f'(y')}{y'-f(y')}dy'},

then we can obtain the general solution..