Calculus/Parametric Differentiation
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[edit] Taking Derivatives of Parametric Systems
Just as we are able to differentiate functions of x, we are able to differentiate x and y, which are functions of t. Consider:


We would find the derivative of x with respect to t, and the derivative of y with respect to t:


In general, we say that if
and
then:
and 
It's that simple.
This process works for any amount of variables.
[edit] Slope of Parametric Equations
In the above process, x' has told us only the rate at which x is change, not the rate for y, and vice versa. Neither is the slope.
In order to find the slope, we need something of the form
.
We can discover a way to do this by simple algebraic manipulation:

So, for the example in section 1, the slope at any time t:

In order to find a vertical tangent line, set the horizontal change, or x', equal to 0 and solve.
In order to find a horizontal tangent line, set the vertical change, or y', equal to 0 and solve.
If there is a time when both x' and y' are 0, that point is called a singular point.
[edit] Concavity of Parametric Equations
Solving for the second derivative of a parametric equation can be more complex that it may seem at first glance. When you have take the derivative of
in terms of t, you are left with
:
.
By multiplying this expression by
, we are able to solve for the second derivative of the parametric equation:
.
Thus, the concavity of a parametric equation can be described as:
![{d\over dt}[{dy \over dx}] \times {dt \over dx}](http://upload.wikimedia.org/math/2/5/8/258ce60575b99a53dfd4c8e840cc50a2.png)
So for the example in sections 1 and 2, the concavity at any time t:
![{d\over dt}[\csc t] \times \cos t = - \csc^2 t \times \cos t](http://upload.wikimedia.org/math/a/e/7/ae7fdd8f44fbf279fc81db0a111c59ad.png)

